3.82 \(\int \frac {1}{1+\cos ^8(x)} \, dx\)

Optimal. Leaf size=129 \[ -\frac {\tan ^{-1}\left (\sqrt {1-\sqrt [4]{-1}} \cot (x)\right )}{4 \sqrt {1-\sqrt [4]{-1}}}-\frac {\tan ^{-1}\left (\sqrt {1+\sqrt [4]{-1}} \cot (x)\right )}{4 \sqrt {1+\sqrt [4]{-1}}}-\frac {\tan ^{-1}\left (\sqrt {1-(-1)^{3/4}} \cot (x)\right )}{4 \sqrt {1-(-1)^{3/4}}}-\frac {\tan ^{-1}\left (\sqrt {1+(-1)^{3/4}} \cot (x)\right )}{4 \sqrt {1+(-1)^{3/4}}} \]

[Out]

-1/4*arctan(cot(x)*(1-(-1)^(1/4))^(1/2))/(1-(-1)^(1/4))^(1/2)-1/4*arctan(cot(x)*(1+(-1)^(1/4))^(1/2))/(1+(-1)^
(1/4))^(1/2)-1/4*arctan(cot(x)*(1-(-1)^(3/4))^(1/2))/(1-(-1)^(3/4))^(1/2)-1/4*arctan(cot(x)*(1+(-1)^(3/4))^(1/
2))/(1+(-1)^(3/4))^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.18, antiderivative size = 129, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 3, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {3211, 3181, 203} \[ -\frac {\tan ^{-1}\left (\sqrt {1-\sqrt [4]{-1}} \cot (x)\right )}{4 \sqrt {1-\sqrt [4]{-1}}}-\frac {\tan ^{-1}\left (\sqrt {1+\sqrt [4]{-1}} \cot (x)\right )}{4 \sqrt {1+\sqrt [4]{-1}}}-\frac {\tan ^{-1}\left (\sqrt {1-(-1)^{3/4}} \cot (x)\right )}{4 \sqrt {1-(-1)^{3/4}}}-\frac {\tan ^{-1}\left (\sqrt {1+(-1)^{3/4}} \cot (x)\right )}{4 \sqrt {1+(-1)^{3/4}}} \]

Antiderivative was successfully verified.

[In]

Int[(1 + Cos[x]^8)^(-1),x]

[Out]

-ArcTan[Sqrt[1 - (-1)^(1/4)]*Cot[x]]/(4*Sqrt[1 - (-1)^(1/4)]) - ArcTan[Sqrt[1 + (-1)^(1/4)]*Cot[x]]/(4*Sqrt[1
+ (-1)^(1/4)]) - ArcTan[Sqrt[1 - (-1)^(3/4)]*Cot[x]]/(4*Sqrt[1 - (-1)^(3/4)]) - ArcTan[Sqrt[1 + (-1)^(3/4)]*Co
t[x]]/(4*Sqrt[1 + (-1)^(3/4)])

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
 FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 3181

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2)^(-1), x_Symbol] :> With[{ff = FreeFactors[Tan[e + f*x], x]}, Dist
[ff/f, Subst[Int[1/(a + (a + b)*ff^2*x^2), x], x, Tan[e + f*x]/ff], x]] /; FreeQ[{a, b, e, f}, x]

Rule 3211

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^(n_))^(-1), x_Symbol] :> Module[{k}, Dist[2/(a*n), Sum[Int[1/(1 - Si
n[e + f*x]^2/((-1)^((4*k)/n)*Rt[-(a/b), n/2])), x], {k, 1, n/2}], x]] /; FreeQ[{a, b, e, f}, x] && IntegerQ[n/
2]

Rubi steps

\begin {align*} \int \frac {1}{1+\cos ^8(x)} \, dx &=\frac {1}{4} \int \frac {1}{1-\sqrt [4]{-1} \cos ^2(x)} \, dx+\frac {1}{4} \int \frac {1}{1+\sqrt [4]{-1} \cos ^2(x)} \, dx+\frac {1}{4} \int \frac {1}{1-(-1)^{3/4} \cos ^2(x)} \, dx+\frac {1}{4} \int \frac {1}{1+(-1)^{3/4} \cos ^2(x)} \, dx\\ &=-\left (\frac {1}{4} \operatorname {Subst}\left (\int \frac {1}{1+\left (1-\sqrt [4]{-1}\right ) x^2} \, dx,x,\cot (x)\right )\right )-\frac {1}{4} \operatorname {Subst}\left (\int \frac {1}{1+\left (1+\sqrt [4]{-1}\right ) x^2} \, dx,x,\cot (x)\right )-\frac {1}{4} \operatorname {Subst}\left (\int \frac {1}{1+\left (1-(-1)^{3/4}\right ) x^2} \, dx,x,\cot (x)\right )-\frac {1}{4} \operatorname {Subst}\left (\int \frac {1}{1+\left (1+(-1)^{3/4}\right ) x^2} \, dx,x,\cot (x)\right )\\ &=-\frac {\tan ^{-1}\left (\sqrt {1-\sqrt [4]{-1}} \cot (x)\right )}{4 \sqrt {1-\sqrt [4]{-1}}}-\frac {\tan ^{-1}\left (\sqrt {1+\sqrt [4]{-1}} \cot (x)\right )}{4 \sqrt {1+\sqrt [4]{-1}}}-\frac {\tan ^{-1}\left (\sqrt {1-(-1)^{3/4}} \cot (x)\right )}{4 \sqrt {1-(-1)^{3/4}}}-\frac {\tan ^{-1}\left (\sqrt {1+(-1)^{3/4}} \cot (x)\right )}{4 \sqrt {1+(-1)^{3/4}}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [C]  time = 0.15, size = 141, normalized size = 1.09 \[ 8 \text {RootSum}\left [\text {$\#$1}^8+8 \text {$\#$1}^7+28 \text {$\#$1}^6+56 \text {$\#$1}^5+326 \text {$\#$1}^4+56 \text {$\#$1}^3+28 \text {$\#$1}^2+8 \text {$\#$1}+1\& ,\frac {2 \text {$\#$1}^3 \tan ^{-1}\left (\frac {\sin (2 x)}{\cos (2 x)-\text {$\#$1}}\right )-i \text {$\#$1}^3 \log \left (\text {$\#$1}^2-2 \text {$\#$1} \cos (2 x)+1\right )}{\text {$\#$1}^7+7 \text {$\#$1}^6+21 \text {$\#$1}^5+35 \text {$\#$1}^4+163 \text {$\#$1}^3+21 \text {$\#$1}^2+7 \text {$\#$1}+1}\& \right ] \]

Antiderivative was successfully verified.

[In]

Integrate[(1 + Cos[x]^8)^(-1),x]

[Out]

8*RootSum[1 + 8*#1 + 28*#1^2 + 56*#1^3 + 326*#1^4 + 56*#1^5 + 28*#1^6 + 8*#1^7 + #1^8 & , (2*ArcTan[Sin[2*x]/(
Cos[2*x] - #1)]*#1^3 - I*Log[1 - 2*Cos[2*x]*#1 + #1^2]*#1^3)/(1 + 7*#1 + 21*#1^2 + 163*#1^3 + 35*#1^4 + 21*#1^
5 + 7*#1^6 + #1^7) & ]

________________________________________________________________________________________

fricas [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+cos(x)^8),x, algorithm="fricas")

[Out]

Timed out

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \mathit {sage}_{0} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+cos(x)^8),x, algorithm="giac")

[Out]

sage0*x

________________________________________________________________________________________

maple [C]  time = 0.07, size = 67, normalized size = 0.52 \[ \frac {\left (\munderset {\textit {\_R} =\RootOf \left (\textit {\_Z}^{8}+4 \textit {\_Z}^{6}+6 \textit {\_Z}^{4}+4 \textit {\_Z}^{2}+2\right )}{\sum }\frac {\left (\textit {\_R}^{6}+3 \textit {\_R}^{4}+3 \textit {\_R}^{2}+1\right ) \ln \left (\tan \relax (x )-\textit {\_R} \right )}{\textit {\_R}^{7}+3 \textit {\_R}^{5}+3 \textit {\_R}^{3}+\textit {\_R}}\right )}{8} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(1+cos(x)^8),x)

[Out]

1/8*sum((_R^6+3*_R^4+3*_R^2+1)/(_R^7+3*_R^5+3*_R^3+_R)*ln(tan(x)-_R),_R=RootOf(_Z^8+4*_Z^6+6*_Z^4+4*_Z^2+2))

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\cos \relax (x)^{8} + 1}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+cos(x)^8),x, algorithm="maxima")

[Out]

integrate(1/(cos(x)^8 + 1), x)

________________________________________________________________________________________

mupad [B]  time = 3.11, size = 1025, normalized size = 7.95 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(cos(x)^8 + 1),x)

[Out]

atan((tan(x)*((2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*8i)/((2^(1/2)*(2*2^(1/2) - 3)^(1/2))/2 - 2^(1/2)/2 - (2
*2^(1/2) - 3)^(1/2) + 1) - (2^(1/2)*tan(x)*((2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*4i)/((2^(1/2)*(2*2^(1/2)
- 3)^(1/2))/2 - 2^(1/2)/2 - (2*2^(1/2) - 3)^(1/2) + 1) - (tan(x)*(2*2^(1/2) - 3)^(1/2)*((2*2^(1/2) - 3)^(1/2)/
128 - 1/128)^(1/2)*8i)/((2^(1/2)*(2*2^(1/2) - 3)^(1/2))/2 - 2^(1/2)/2 - (2*2^(1/2) - 3)^(1/2) + 1) + (2^(1/2)*
tan(x)*(2*2^(1/2) - 3)^(1/2)*((2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*4i)/((2^(1/2)*(2*2^(1/2) - 3)^(1/2))/2
- 2^(1/2)/2 - (2*2^(1/2) - 3)^(1/2) + 1))*((2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*2i - atan((tan(x)*(- (2*2^
(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*8i)/((2^(1/2)*(2*2^(1/2) - 3)^(1/2))/2 + 2^(1/2)/2 - (2*2^(1/2) - 3)^(1/2)
 - 1) - (2^(1/2)*tan(x)*(- (2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*4i)/((2^(1/2)*(2*2^(1/2) - 3)^(1/2))/2 + 2
^(1/2)/2 - (2*2^(1/2) - 3)^(1/2) - 1) + (tan(x)*(2*2^(1/2) - 3)^(1/2)*(- (2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1
/2)*8i)/((2^(1/2)*(2*2^(1/2) - 3)^(1/2))/2 + 2^(1/2)/2 - (2*2^(1/2) - 3)^(1/2) - 1) - (2^(1/2)*tan(x)*(2*2^(1/
2) - 3)^(1/2)*(- (2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*4i)/((2^(1/2)*(2*2^(1/2) - 3)^(1/2))/2 + 2^(1/2)/2 -
 (2*2^(1/2) - 3)^(1/2) - 1))*(- (2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*2i + atan((tan(x)*(- (- 2*2^(1/2) - 3
)^(1/2)/128 - 1/128)^(1/2)*8i)/((2^(1/2)*(- 2*2^(1/2) - 3)^(1/2))/2 + 2^(1/2)/2 + (- 2*2^(1/2) - 3)^(1/2) + 1)
 + (2^(1/2)*tan(x)*(- (- 2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*4i)/((2^(1/2)*(- 2*2^(1/2) - 3)^(1/2))/2 + 2^
(1/2)/2 + (- 2*2^(1/2) - 3)^(1/2) + 1) + (tan(x)*(- 2*2^(1/2) - 3)^(1/2)*(- (- 2*2^(1/2) - 3)^(1/2)/128 - 1/12
8)^(1/2)*8i)/((2^(1/2)*(- 2*2^(1/2) - 3)^(1/2))/2 + 2^(1/2)/2 + (- 2*2^(1/2) - 3)^(1/2) + 1) + (2^(1/2)*tan(x)
*(- 2*2^(1/2) - 3)^(1/2)*(- (- 2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*4i)/((2^(1/2)*(- 2*2^(1/2) - 3)^(1/2))/
2 + 2^(1/2)/2 + (- 2*2^(1/2) - 3)^(1/2) + 1))*(- (- 2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*2i - atan((tan(x)*
((- 2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*8i)/((2^(1/2)*(- 2*2^(1/2) - 3)^(1/2))/2 - 2^(1/2)/2 + (- 2*2^(1/2
) - 3)^(1/2) - 1) + (2^(1/2)*tan(x)*((- 2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*4i)/((2^(1/2)*(- 2*2^(1/2) - 3
)^(1/2))/2 - 2^(1/2)/2 + (- 2*2^(1/2) - 3)^(1/2) - 1) - (tan(x)*(- 2*2^(1/2) - 3)^(1/2)*((- 2*2^(1/2) - 3)^(1/
2)/128 - 1/128)^(1/2)*8i)/((2^(1/2)*(- 2*2^(1/2) - 3)^(1/2))/2 - 2^(1/2)/2 + (- 2*2^(1/2) - 3)^(1/2) - 1) - (2
^(1/2)*tan(x)*(- 2*2^(1/2) - 3)^(1/2)*((- 2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*4i)/((2^(1/2)*(- 2*2^(1/2) -
 3)^(1/2))/2 - 2^(1/2)/2 + (- 2*2^(1/2) - 3)^(1/2) - 1))*((- 2*2^(1/2) - 3)^(1/2)/128 - 1/128)^(1/2)*2i

________________________________________________________________________________________

sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+cos(x)**8),x)

[Out]

Timed out

________________________________________________________________________________________